16x^2+480x+3600=256x^2

Solution for 16x^2+480x+3600=256x^2 equation:

16x^2+480x+3600=256x^2

We move all terms to the left:

16x^2+480x+3600-(256x^2)=0

determiningTheFunctionDomain
16x^2-256x^2+480x+3600=0

We add all the numbers together, and all the variables

-240x^2+480x+3600=0

a = -240; b = 480; c = +3600;
Δ = b2-4ac
Δ = 4802-4·(-240)·3600
Δ = 3686400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3686400}=1920$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(480)-1920}{2*-240}=\frac{-2400}{-480}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(480)+1920}{2*-240}=\frac{1440}{-480}
=-3
$